Array that contains a geometric series

38 次查看（过去 30 天）
shir shalom
shir shalom 2016-12-19
评论： shir shalom 2016-12-20
Hi, Is there a short way to create an array in which the elements are making a geometric series?
like for example the following array:
x=[1 2 4 8 16 32 64]
Thanks, Shir

请先登录，再回答此问题。

采纳的回答

Roger Stafford
Roger Stafford 2016-12-19
A general form for a geometric series is:
[a,a*r,a*r^2,a*r^3,...]
You can generate n of these by:
s = a*r.^(0:n-1);

更多回答（1 个）

John D'Errico
John D'Errico 2016-12-19
2.^(0:6)
  3 个评论
显示 1更早的评论
John D'Errico
John D'Errico 2016-12-19
You could have said that the first time. But what is wrong then with this?
2.^(-1:6)
It really won't work? I guess I need to learn this new math then.
Or, for a more general form, with some other start point:
0.1*2.^(0:6)
Could I have used a loop? Of course. But why? Learn to use Matlab.
shir shalom
shir shalom 2016-12-20
Yes, sorry of course it works. I guess I was too tired to think last night. Thanks alot!

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Mathematics 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by