how to refine data?

1 次查看（过去 30 天）
Darkhan Kenestegi
Darkhan Kenestegi 2016-12-27
编辑： KSSV 2016-12-27
Let's say I have a data matrix as:
a=[1,1,1,1,1;1,0,1,1,0;0,0,0,1,1;1,0,1,0,1];
Now, what I want is to get rid of the zeroes, yet not messing up my matrix. As of I need values stay at their corresponding rows. Reason I want it is due to my original data having 0 and I need to calculate log of each values in the row. Ln(0) simply is messing my code for obvious reason.
Will really appreciate the help!
  2 个评论
KSSV
KSSV 2016-12-27
编辑：KSSV 2016-12-27
You cannot get rid of zeros without disturbing the dimensions. The option would be to replace zeros with some other number. Is it okay to replace with nan?
Also not that log(1) is 0.
Darkhan Kenestegi
Darkhan Kenestegi 2016-12-27
Thanks for the answer, yeah I know, probably I used a bad example, just created a matrix out of my head really. My data is just quite big and checking each row individually is just not an option.
I get that it won't be possible without disturbing the dimensions, makes sense.
Actually later in the code I do get NaN instead of zeroes in the matrix. Are you suggesting that I can code it in such a way that I can neglect those NaN values and concentrate on real values? But the question then switches on how to get rid of NaN?
Thanks for your support!

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

KSSV
KSSV 2016-12-27
编辑：KSSV 2016-12-27
How about this?
a=[ 0.2077 0.2305 0.8443 0.1707 0.3111
0.3012 0 0.1948 0.2277 0
0 0 0 0.4357 0.9234
0.4709 0 0.2259 0 0.4302];
idx = a~=0 ;
%%apply log
log_a = a;
log_a(idx) = log(a(idx)) ;
log_a

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by