Finding epsilon satisfy a trigonometric function.
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I need to find the value of epsilon (e) that satisfy the function cot(e)^2*cot(2*e)^2 == sin(2*e)^2 where pi/4<e<pi/2
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sawsan
2016-12-31
编辑：Walter Roberson
2017-1-3
3 个评论
Star Strider
2016-12-31
There are 4 solutions on the interval (-pi/2,pi/2).
Sawsan Alhowaity
2017-1-3
yes, but on the interval [pi/3, pi/2] there is only one solution. Thanks for replying.
Star Strider
2017-1-3
Your original Question asked for all solutions on the interval -pi/2 to pi/2.
更多回答（2 个）
KSSV
2016-12-27
clc; clear all ;
syms e
eqn = cot(e)^2*cot(2*e)^2 == sin(2*e)^2 ;
[solx, params, conds] = solve(eqn, e, 'ReturnConditions', true) ;
Star Strider
2016-12-27
Another approach:
trig_e = @(e) cot(e).^2*cot(2*e).^2 - sin(2*e).^2;
v = linspace(-pi/2, pi/2, 4);
for k1 = 1:length(v)
e(k1) = fzero(trig_e, v(k1));
end
e =
-1.3267e+000 -541.3248e-003 541.3248e-003 1.3267e+000
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