How to declare a function using the diff-command

2016 12 28
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In Matlab I am given a function whose declaration starts with this code:
function [v1, v2, v3, v4, v5, v6] = calculate_v(P1, P2, angle, difference)
dP1=P1(2) - P1(1);
dangledP1=diff(angle)/dP1;
dP2dP1=diff(P2)/dP1;
But I don't understand it. The input variables seem to be vectors. I know the diff-command returns a vector whose entries are the difference of adjacent entries. But what is happening in the first line:
dP1 = P1(2) - P1(1) ?
I mean does P1 only have two entries? I am not given any further information about the variables either.

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KSSV
KSSV 2016-12-28

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You have to enter at least two entries for P1, dP1=P1(2) - P1(1) is like calculating the difference/ step. If you enter more then two elements also, your code will not take the other values into consideration.

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Luki
Luki 2016-12-28
Ok. So the difference to diff(P1) is that P1(2)-P1(1) would only equal the first entry of diff(P1)
KSSV
KSSV 2016-12-28
编辑：KSSV 2016-12-28
No diff(P1) calculates the difference P(i)-P(i+1)..._diff_ calculates the difference among the successive elements and it's size would be one less then the input vector. In your code there is no diff(P1).

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Luki
Luki
2016-12-28

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KSSV
KSSV
2016-12-28

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