use regexp to find specific names.

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FaryTak
FaryTak 2016-12-31
编辑： per isakson 2017-1-19
Hi
I've been trying to download some specific files from the web with name
'DPR-NS-12755-V04A.MRMS-XXXXXXXX.114200.matched-130W_55W_20N_55N.extract.dat'
The XXXXXXXX is the yyyymmdd that changes with the loop. I used regexp. But it returns just XXXXXXXX and not the entire name. I used something ugly (which worked finally) to download my file as:
expr = [sprintf('%02.0f', y), sprintf('%02.0f', m), sprintf('%02.0f', d)];
% y = year, m = month, d is day
a = regexp(str,expr);
filename=str(a-22:a+51);
I know it is very armature to use something like this!. Can you help me to parcel the name of these files in a more professional way? I read the regexp doc in Matlab but it is a little confusing for me.
Thanks,
Zeinab

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回答（1 个）

mizuki
mizuki 2016-12-31
Use datetime instead of regular expressions:
% from 2016/12/01 to 2016/12/10 with every other day
datevec = datetime(2016,12,01):day(2):datetime(2016,12,10);
t = datestr(datevec, 'yyyymmdd');
for i = 1:size(t,1)
filename = ['DPR-NS-12755-V04A.MRMS-', t(i,:), '114200.matched-130W_55W_20N_55N.extract.dat'];
% webread(filename)
end
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per isakson
per isakson 2016-12-31
How do you know the name of the day?
FaryTak
FaryTak 2016-12-31
I know there is one file for each day. I can find them by YYYYMMDD going through each day of a year. But the rest of the name starts with "DPR" and ends with ".dat". the other parts of the file's names are unknown.

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