How to take elements row wise or column wise in a 2d array
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A is a 5*5 array. Its needed to take 7 elements along the 1st column and 2 from the beginning of 2nd column.So the window size is 7.Now that makes it possible to take 3 windows.So 4 elements are left.this last window should be 4 leftover elements and rest zeroes.How to have a loop that gives me the 4 windows in a variable
3 个评论
per isakson
2016-12-31
Without a loop
>> A=magic(5);
>> reshape( [A(:);zeros(3,1)], [7,4] )
ans =
17 6 25 16
23 12 8 22
4 18 14 3
10 1 20 9
11 7 21 0
24 13 2 0
5 19 15 0
MSP
2017-1-1
编辑：per isakson
2017-1-1
per isakson
2017-1-1
In your question you say
- "a 5*5 array"  
- "take 7 elements [window] along"  
- "that gives me the 4 windows in a variable"  
- "matrix signalprocess"  
"generalize"   Yes, but in what way? Arbitrary size of the input matrix and/or the window? Along columns or rows? ...
采纳的回答
Walter Roberson
2016-12-31
buffer(A(:), 7)
1 个评论
Walter Roberson
2017-1-1
window = 7;
A = randi(5,5);
n = numel(A);
left_over = mod(n, window);
if left_over == 0
stream = A(:);
else
stream = [A(:); zeros(window - left_over, 1)];
end
output = reshape(stream, window, []);
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