Error using min Matrix dimensions must agree.
显示 更早的评论
Greetings ... I will be new in matlab and in this community, I am going to you because I have a small problem with a project, which tries to make a fuzzy controller ... I got a code from a controller that made a few Changes insignificant, but it is not working, and shows me an error in the use of the min () function. Someone who can help me with this problem please
%
paso = 0.01;
valCong=0:paso:1;
PC=trapmf(valCong,[0 0 0.1 0.35]);
MC=trimf(valCong,[0.2 0.5 0.8]);
AC=trapmf(valCong,[0.65 0.9 1 1]);
paso2=0.1;
tiempo=0:paso2:55;
PTV=trapmf(tiempo,[0 0 7.5 15]);
MTV=trimf(tiempo,[10 27.5 45]);
LTV=trapmf(tiempo,[40 47.5 55 55]);
nivCong=0.5;
n=find(valCong==nivCong);
B1 = min(PTV,PC(n));
B2 = min(MTV,MC(n));
B3 = min(LTV,AC(n));
B = max(B1,max(B2,B3));
TV = defuzz(tiempo,B,'centroid');
tiempoVerde=round(TV,0);
Este codigo me da el siguiente error
"Error using min
Matrix dimensions must agree.
Error in Oquendo_Calama (line 53)
B1 = min(PTV,PC(n));"
回答（2 个）
John D'Errico
2017-1-11
编辑：John D'Errico
2017-1-11
0 个投票
Apparently, PTV is a matrix. Right? What size is that matrix?
Apparently, PC(n) is a matrix. Right? What size is that matrix?
They are not the same size. Read the error message. What sense would it make to try to take the min between a 3x3 and a 2x2 matrix? None. While I don't know the actual sizes of your matrices, the above statement still applies.
1 个评论
Stephen23
2017-1-11
What happens is that I try to do is to program my own fuzzy controller, and that's why I'm not using Fuzzy Logic Toolbox, so far as PTV and PC are not actually arrays but rather they are fuzzy sets, and I explained that "B1 = Min (PTV, PC (n)) "makes a cut of the PTV set at the height of the fusing value 'n' and that value stores it in B1
Walter Roberson
2017-1-11
Your find() operation is returning the empty matrix for n.
You have find(valCong==nivCong) which attempts to check for bit-for-bit equality between the floating point number nivCong in the vector 0:paso:1 where paso is not an integer (paso = 0.01). Due to accumulated floating point roundoff, there might not be any entry that exactly equals 0.5.
You should consider using
[tf, n] = ismembertol(nivCong, valCong);
and you should check to be sure that tf returns true (if it is false, no entries matched to within tolerance.)
类别
在 帮助中心 和 File Exchange 中查找有关 Fuzzy Logic in Simulink 的更多信息
2017-1-11
2017-1-11
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
