how to use fir1 function?
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In fir1 one argument is Wn. I can't understand how its possible to create filter without specify the real frequency? For example, if I try to run low-pass fir filter with Wn=0.5 on two signals, one with Fs=1000 and one with Fs=10,000 how the filter can "know" what frequency is Wn=0.5 to perfom the low-pass filtering on each signal? thank you
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Star Strider
2017-1-15
The ‘Wn’ argument expresses the normalised frequencies for the passbands and stopbands. That means that for a discrete filter, these are already on the interval (0,pi), where pi is defined as the Nyquist frequency (half the sampling frequency). So that information is inherent in the ‘Wn’ argument, even if not explicitly stated.
If you use a window function (such as I did here in a code snippet from another Answer):
fcuts = [0.08 0.19]; % Frequency Vector
mags = [1 0]; % Magnitude (Defines Passbands & Stopbands)
devs = [0.01 0.05]; % Allowable Deviations
[n,Wn,beta,ftype] = kaiserord(fcuts,mags,devs,Fs); % Kaiser Window
n = n + rem(n,2);
hh = fir1(n,Wn,ftype,kaiser(n+1,beta),'scale'); % Design FIR Lowpass Filter
the window function incorporates the sampling information (in ‘Fs’, the last argument to kaiserord here) and then presents fir1 with the normalised passbands and stopbands.
4 个评论
nadav potasman
2017-1-15
Star Strider
2017-1-15
My pleasure.
Yes. You can use the same filter with different values for ‘Fs’, but the passbands and stopbands will change with the value of ‘Fs’ changes.
For example, if you have a lowpass filter with a stopband of 0.5*pi radians, with a sampling frequency of 1000 Hz, the stopband will be 250 Hz (since Fn = 500) where ‘Fn’ is the Nyquist frequency. For a sampling frequency of 44100 Hz, the stopband for the same filter will be 11025 Hz.
nadav potasman
2017-1-15
Star Strider
2017-1-15
My pleasure!
If my Answer helped you solve your problem, please Accept it!
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