How to read multiple jpg images in matlab

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djamaleddine djeldjli
评论： djamaleddine djeldjli 2017-1-21
i have 250 jpg images stored at in_dir = 'C:\Users\DJDJ\Desktop\pic';
these pictures are arranged as following and named : image1 , image2, image3.....image250
I want to read all these images and processing them starting by image1 after processing go to process image2 .and after image3.to..image250
then saved the resultant images after preproceesing in a specific file,for example at out_dir = 'C:\Users\DJDJ\Desktop\pic output';.
How can i do this in matlab?
thank you in advance

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采纳的回答

Niels
Niels 2017-1-20
编辑：Niels 2017-1-20
you can use a for loop and save the image data in a cell:
replace png by the file type of your images. result will be a 1x250 cell array
for i= 1:250
x{i}=imread(['image',num2str(i),'.png'])
end
>> save('image_Data','x')
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Image Analyst
Image Analyst 2017-1-21
You need to use exist() to verify that the file exists first. Also, splitting up long lines into multiple lines would make things simpler. Because of that, I can see that you totally ignored my answer to use the code in the FAQ and used your own code, thus causing your problems. I urge you to again look at the FAQ and see what it's doing that you aren't, and then the code will work.
djamaleddine djeldjli
djamaleddine djeldjli 2017-1-21
Thank you very much for your assistance.Now,it's working well.
I have replaced line 11 by current_image = imread(fullfile(in_dir, fname));

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Image Analyst
Image Analyst 2017-1-21
You would use the first code sample in this entry of the FAQ: http://matlab.wikia.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F
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Maitham
Maitham 2017-1-21
Hi Image Analyst. Sorry maybe my comment has not related to this topic. I need your help please with Strehl Ratio. I have a point source image and need to find and draw the Strehl Ratio for it. I would high appreciate it if you could help me please. Very kind regards Maitham
Image Analyst
Image Analyst 2017-1-21
Read this link and then attach your data in a new question. We can't do anything without data to work on.

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