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time format as hr:min:sec

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seema niran
seema niran 2017-1-23
回答： Peter Perkins 2017-2-6
sir, i have three columns- one containing hour, next minute , third on sec.
hr=[10,10,10,10];
min=[00,00,01,01];
sec=[00,30,00,30];
i need a single column of time as
[10:00:00,10:00:30,10:01:00,10:01:30]
what is the method?

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采纳的回答

KSSV
KSSV 2017-1-23
hr=[10,10,10,10];
min=[00,00,01,01];
sec=[00,30,00,30] ;
iwant = [] ;
for i = 1:length(hr)
str = sprintf('%02d:%02d:%02d\n',hr(i),min(i),sec(i)) ;
iwant = [iwant ; str] ;
end
iwant
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seema niran
seema niran 2017-2-6
sir, it is correct. the 707th term in data was a negetive one making all the problem. thanks
Stephen23
Stephen23 2017-2-6
@seema niran: note that my Answer works with negative values as well, without error, as well as being simpler and much more efficient that the answer you accepted.

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更多回答（2 个）

Stephen23
Stephen23 2017-1-23
编辑：Stephen23 2017-1-23
>> hr=[10,10,10,10];
>> min=[00,00,01,01];
>> sec=[00,30,00,30];
>> fprintf('%02d:%02d:%02d\n',[hr;min;sec])
10:00:00
10:00:30
10:01:00
Or to put it into a string or cell array:
>> S = sprintf('%02d:%02d:%02d\n',[hr;min;sec])
S =
10:00:00
10:00:30
10:01:00
>> C = strsplit(strtrim(S),'\n')'
C =
'10:00:00'
'10:00:30'
'10:01:00'
'10:01:30'
Peter Perkins
Peter Perkins 2017-2-6
All the previous answers assume you want text, and that may be what you want. But if you're using R2014b or later, you can use durations:
>> hr=[10,10,10,10];
>> min=[00,00,01,01];
>> sec=[00,30,00,30];
>> d = duration(hr,min,sec)
d =
10:00:00 10:00:30 10:01:00 10:01:30

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