2 个投票

Is there a more elegant way to do this, so you don't have to write every separate cell array index?
fprintf(fidw,[repmat('%s,',1,25) '%s\n'] ... ,sHeads{1},sHeads{2},sHeads{3},sHeads{4},sHeads{5},sHeads{6},sHeads{7},sHeads{8},sHeads{9},sHeads{10},sHeads{11},sHeads{12} ... ,sHeads{13},sHeads{14},sHeads{15}

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Star Strider
Star Strider 2017-1-23

11 个投票

See if this does what you want:
cstr = {'The' 'quick' 'brown' 'fox'};
fprintf(1, '%s - ', cstr{:})
fprintf(1, '\n')
writes to the Command Window:
The - quick - brown - fox -

3 个评论
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Richard
Richard 2017-1-23
Thanks Star Strider!!! The ":" was the key that I needed. I like this: fprintf( fidw, [repmat('%s,',1,25) '%s\n'], sHeads{:} );
Star Strider
Star Strider 2017-1-23
My pleasure!
Thank you! This helped me on my final project

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Ali Öztürk
Ali Öztürk 2021-6-20

1 个投票

if you use both cell and matrix.
seven={'ali';'hilal'};
sevilen={'hilal';'ali'};
sevgisi=[100;0];
for i=1:size(seven,1)
fprintf('%s (n)in %s (y)e sevgisi %d\n',seven{i},sevilen{i},sevgisi(i));
end
writes to the Command Window:
ali (n)in hilal (y)e sevgisi 100
hilal (n)in ali (y)e sevgisi 0

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Exactly what I was looking for -- thank you!
Alireza
Alireza 2024-10-1
God bless you brother, you solved my problem.

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