logical indexing

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Thijs
Thijs 2012-3-14
imagine you have a two matrixes:
a=[1 2 3 4 5 6 7 8 9];
b=[1 0 1 0 1];
how do i use the b matrix as a logical index? I'd expect:
a(b)
ans =
[1 3 5]
but instead i get the error: "Subscript indices must either be real positive integers or logicals."
if I try
a(~b)
ans =
[2 4]
now I could use a(~~b) which does what i want but this seems inelegant. Can anyone suggest a better solution?

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采纳的回答

Jacob Halbrooks
Jacob Halbrooks 2012-3-14
Use LOGICAL to do the type conversion:
a(logical(b))

更多回答（4 个）

Aldin
Aldin 2012-3-14
Here:
for i = 1:5
if b(i) == 1
disp(a(i))
end
end
:)
  6 个评论
显示 4更早的评论
Aldin
Aldin 2012-3-14
result =
1 3 5
Aldin
Aldin 2012-3-14
Here is another solution:
a(b(1:5)==1)

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Thijs
Thijs 2012-3-14
a(logical(b)) does what I want. In case anyone else is wondering
  2 个评论
Aldin
Aldin 2012-3-14
See above it's similiar with my solution :)
Thijs
Thijs 2012-3-14
true, thanks

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Onomitra Ghosh
Onomitra Ghosh 2012-3-14
Your "b" matrix is in double. You need to convert that to logical values for logical indexing:
>> a(boolean(b))
ans =
1 3 5
Aldin
Aldin 2012-3-14
but what if you haven't only '1' and '0' in b array. I think it's better my first solution or second &Onomitra Ghosh his code with logical work correctly

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