I can't use int for functions

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f4r3in
f4r3in 2017-1-29
编辑： Star Strider 2017-1-29
I use Matlab R2016a. I write a function but I can't use int to get integrate:
function y=g1(x)
if x>0
y=1;
else
y=-1;
end
end
and when I run :" int(g1) " I receive this error :
int(g1)
Not enough input arguments.
Error in g1 (line 2)
if x>0
what should I do. please help step by step because I am beginner.

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回答（1 个）

Star Strider
Star Strider 2017-1-29
编辑：Star Strider 2017-1-29
Your ‘g1’ is a function, so you have to pass it the argument you wrote it to evaluate. The integral function does this implicitly (so you do not actually see it).
I would use the integral function, not the Symbolic Math Toolbox int function (unless you have to do this symbolically):
g1 = @(x) (x>0).*(1) + (x<=0).*(-1);
a = -pi;
b = pi;
Result = integral(g1, a, b);
I used ‘logical indexing’ to define ‘g1’ here. It is more efficient.

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