How to plot the equation |x|+|y|+|z|=1 ?

47 次查看（过去 30 天）
Jes
Jes 2017-1-30
评论： Walter Roberson 2017-1-30
I have a 3D equation. Can anyone help me to plot this? Thanks

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回答（2 个）

Benjamin Kraus
Benjamin Kraus 2017-1-30
编辑：Benjamin Kraus 2017-1-30
If you are using MATLAB R2016b you can use the new fimplicit3 command:
fimplicit3(@(x,y,z) abs(x)+abs(y)+abs(z)-1)
You may also be interested in fplot, fplot3, fsurf, fmesh, fcontour, and fimplicit (some of these have been available since R2016a, but fimplicit3 was added in R2016b).
John Chilleri
John Chilleri 2017-1-30
编辑：John Chilleri 2017-1-30
Hello,
I'm certain there's a better way to do this, such as with surf, but here is a solution.
If you consider the equation, you realize that it's all planes joined by the 6 vertices {(1,0,0),(0,1,0),(0,0,1),(-1,0,0),(0,-1,0),(0,0,-1)}. These 6 vertices 'form' 8 sides.
Using the fill3 command, you can reconstruct the shape:
fill3([1 0 0],[0 1 0],[0 0 1], 'r')
hold on
fill3([1 0 0],[0 1 0],[0 0 -1], 'r')
fill3([1 0 0],[0 -1 0],[0 0 -1], 'r')
fill3([-1 0 0],[0 -1 0],[0 0 -1], 'r')
fill3([-1 0 0],[0 -1 0],[0 0 1], 'r')
fill3([-1 0 0],[0 1 0],[0 0 1], 'r')
fill3([-1 0 0],[0 1 0],[0 0 -1], 'r')
fill3([1 0 0],[0 -1 0],[0 0 1], 'r')
which results in the following image:
(This is just an angle I chose to show.)
Hope this helps!
  1 个评论
John Chilleri
John Chilleri 2017-1-30
If you are running R2016b, Benjamin Kraus has the smart solution! I'm running R2015b, and I would encourage my solution only if you are running an older release.

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