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How to create cross-section from 3d dimensional surface?

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Hassan Khoshzaban 2017-1-31

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评论： Hassan Khoshzaban 2017-2-11

采纳的回答： KSSV

I transported the simulated surface's data as three (20x20) matrices X,Y,Z. So, I have a 3D plot that's generated by 3 (20x20) matrices X,Y,Z. I want to plot the YZ curve (cross section) at specified X. Moreover, the dimension of surface is really important to me, and I do not want to miss my surface feature or profile by interpolation?

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KSSV 2017-1-31

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编辑：KSSV 2017-1-31

You define your required x values and the respective y values, use interpolation (interp2).

Read about interp2 .

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Hassan Khoshzaban 2017-1-31

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Thanks KSSV for your attention x,y,z are three 20*20 matrices. I defined the Y and Z values for meshgrid and desired X's. Then, I tried to get V=X,Y,Z; but the (interp2) Vq = interp2(X,Y,V,Xq,Yq) did not work. can you help me with more details?

KSSV 2017-1-31

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在 MATLAB Online 中打开

[X,Y,Z] = peaks(20);
%
x0 = min(X(:)) ; x1 = max(X(:)) ;
yo = min(Y(:)) ; y1 = max(Y(:)) ;
% interpolation 
xi = zeros(1,20) ;
yi = Y(:,1) ;
zi = zeros(size(xi)) ;
for i = 1:length(xi)
    zi(i) = interp2(X,Y,Z,xi(i),yi(i)) ;
end
surf(X,Y,Z) ;
hold on
plot3(xi,yi,zi,'.-r') ;

Hassan Khoshzaban 2017-1-31

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2017-01-31_18-41-35.png

There is a problem about my surface (yellow). It consists of 400 points with different distance. It has not continious meshgrid. In fact, blue surface doesn't cut the yellow one in positions where fit by 400 points positions. I attach the pic to make it sence.

KSSV 2017-1-31

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Doesn't matter.....it will work. You attach your data and show me where you want to extract the data.

Hassan Khoshzaban 2017-1-31

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data.mat

I attach my matrices. I want to get YZ curves for different X (e.g. YZ curve for X=-5.4) Thanks

KSSV 2017-1-31

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编辑：KSSV 2017-1-31

在 MATLAB Online 中打开

load data.mat ;
surf(X,Y,Z) ;
%
x0 = min(X(:)) ; x1 = max(X(:)) ;
y0 = min(Y(:)) ; y1 = max(Y(:)) ;
%
N = 20 ;
xi = -5.4013*ones(1,N) ;
% yi = linspace(1.6496,1.7752,N) ;
yi = linspace(y0,y1,N) ;
zi = zeros(size(xi)) ;
P = [X(:),Y(:)] ; V = Z(:) ;
F = scatteredInterpolant(P,V) ;
F.Method = 'natural';
F.ExtrapolationMethod = 'none' ;
% Take points lying insuide the region
pq = [xi',yi'] ; 
Vq = F(pq) ;
zi = Vq ;
hold on
plot3(xi,yi,zi,'.-r')

Hassan Khoshzaban 2017-1-31

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Thanks KSSV Your attention is highly appreciated

KSSV 2017-1-31

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编辑：KSSV 2017-1-31

Does it solve your purpose?

I made few changes to the above code, you may have a look now. Earlier you had to specify y values for yi, now it is not needed. You may specify your required xi value and proceed.

Hassan Khoshzaban 2017-1-31

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The upper point well match with surface. There is a mismatch for first node. Is there any way to fit the nodes with surface by high accuracy. Anyway, your help regarding above code is really great.

KSSV 2017-1-31

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It can be done, but depends on how accurate your xi,yi belong to X,Y

Hassan Khoshzaban 2017-2-11

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13.png

Hi I tried this code for my whole surface (23x110 matrix). It showed the misconsistency because of different degree of linearity. Is it possible to increase accuracy with using mesh grid between elements. I attach the image to show you problem. Thanks

Hassan Khoshzaban 2017-2-11

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matrix.mat

I attach matrixes to make it sence.

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