Vector/matrix Initialization
35 次查看(过去 30 天)
显示 更早的评论
Matlab newbie here, so be gentle.
I am trying to port some Matlab code to C/C++ and am struggling to understand some of the syntax.
In particular, the following code segment eludes me:
if i0<i1
k=[i1 i i0];
elseif i0>i
k=[i0 i1 i];
elseif i1<i
k=[i i0 i1];
end
v=1:length(s);
v(k(1))=[];
v(k(2))=[];
v(k(3))=[];
for k=1:length(v)
px=s(v(k),1);
py=s(v(k),2);
end;
As I understand it, the first if-then block creates k as a one row, three column matrix. I am simply lost by the next code block. Any help in understanding what it means (especially in C/C++ form) appreciated.
Thanks
0 个评论
采纳的回答
Stephen23
2017-2-2
编辑:Stephen23
2017-2-2
The first two blocks don't make much sense. Assuming that the one of those if conditions is true then vector k will get defined with the same three value (in different orders). The vector k is then used to remove some values from v, but the order is irrelevant. k is not used again (it gets reassigned in the third block of code). Therefore the first two blocks are simply equivalent to:
v = 1:length(s);
v([i1,i,i0]) = [];
9 个评论
Stephen23
2017-2-2
编辑:Stephen23
2017-2-2
@James Pistorino: to learn the basics of MATLAB you should work through these tutorials (they will not take long if you have experience with other languages, but will introduce you to some extremely fundamental concepts, especially code vectorization):
And you might like to read this too:
PS: when you write your own MATLAB code avoid using length: use size or numel.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!