difference between hours, minutes and seconds

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elisa ewin
elisa ewin 2017-2-2
回答： Steven Lord 2017-2-2
Hi!
I have matrix A
M=[8 8 48;8 15 29;9 30 15;9 48 53;9 49 30;9 52 12;9 57 0;10 2 27;10 28 52;11 29 47;11 43 41;11 44 4];
The first column of the matrix indicates hours, the second minutes and the third seconds. I want to calculate the difference between consecutive rows
Eg.
M(2,1:3)-M(1,1:3) = 0 6 41
Can you help me? Thanks

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采纳的回答

Star Strider
Star Strider 2017-2-2
See if this does what you want:
M=[8 8 48;8 15 29;9 30 15;9 48 53;9 49 30;9 52 12;9 57 0;10 2 27;10 28 52;11 29 47;11 43 41;11 44 4];
Mdn = datenum([repmat([2017 02 02], size(M,1), 1) M]); % Date Numbers
Mdndif = datevec(diff(Mdn)); % Date Number Differences As Date Vectors
Out = Mdndif(:, 4:end) % Desired Result
Out =
0 6 41
1 14 46
0 18 38
0 0 37
0 2 42
0 4 48
0 5 27
0 26 25
1 0 55
0 13 54
0 0 23

更多回答（2 个）

Jan
Jan 2017-2-2
编辑：Jan 2017-2-2
D = diff(M, [], 1);
DinSec = D * [3600; 60; 1] / 86400; % difference in seconds
S = datevec(DinSec);
Result = M(:, 4:6)
Steven Lord
Steven Lord 2017-2-2
Use a duration object.
% Sample data
M = [ 8 8 48; 8 15 29; 9 30 15; 9 48 53; 9 49 30; 9 52 12; ...
9 57 0; 10 2 27; 10 28 52; 11 29 47; 11 43 41; 11 44 4];
% Convert from numbers to a duration array
dur = duration(M);
% Compute the DIFFerence between the rows of the duration array
Ddur = diff(dur, [], 1);
% Extract the hour, minute, and second data from Ddur
% and store that data in the matrix DM
[DM(:, 1), DM(:, 2), DM(:, 3)] = hms(Ddur);
% Show the result
disp(DM)

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