Finding zero poles in eigenvalues
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Hello Matlab Community, I have problems finding the zero pole of my eigenvalues of a matrix. I have a given 4x4 matrix A:
A=[0 1 0 0;
-35.7 -d/841.5 35.7 d/841.5;
0 0 0 1;
1200 d/25 -9200 (-100-d)/25];
lambda=eig(A);
I can imagine the code to be something like: find(min(real(lambda(1)-lambda(2)))&&min(imag(lambda(1)-lambda(2))));
I can change the value of d within a given range of 800 till 12000;
As you can see in the picture, the steps at the results get even bigger, so a loop didn't really do the trick for me, as I would need to adapt the stepsize of d when I get closer to my desired result.
Could it be possible to solve this problem with fminsearch(@d eig(A))? I have no idea how to get the matrix into my fminsearch function.
Would be nice if no optimization toolbox is needed.
Thank you for your help.
回答（1 个）
Star Strider
2017-2-3
0 个投票
If I remember correctly, the eigenvalues of the ‘A’ matrix of a control system are the poles. To find the zeros of your system, you first need to convert it to a transfer function.
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2017-2-3
2017-2-3
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