Extract every second value of a vector and write into a new vector
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Hi, another trivial question i guess - i'm a beginner at Matlab.
MATLAB code
Xi = sym('Xi',[1,n2]);
for i=1:1:6
BGx(i,1)=L1*Xi(i);
BGy(i,1)=L5*Xi(i);
end
I want to write the results into a new vector. I tried vertcat and some for loops but it didn't work out.
MATLAB code
BG=vertcat(BGx; BGy);
Here i get a result like (L1*Xi1, L1*Xi2, L1*Xi3, ...., L5*Xi1, ...., L5*Xi6) but i want to get (L1*Xi1, L5*Xi1, L1*Xi2, L5*Xi2, ...., L5*Xi6). Is there a trick when using vertcat or do i need to write a loop. I have the problem that BG has another dimension than the 2 vectors BGx and BGy. Thanks in advance
采纳的回答
Niels
2017-2-3
result = zeros(12,0);
for i=1:1:6
result((i-1)*2+1)=BGx(i,1);
result(i*2)=BGy(i,1);
end
更多回答(1 个)
Stephen23
2017-2-3
编辑:Stephen23
2017-2-3
This is MATLAB so why use an ugly loop? MATLAB is much better than that! The code is simpler without it (I also got rid of sym: you don't say why you need it, and numeric operations will be much faster and more efficient):
>> X = [1,2,3,4];
>> L1 = 90;
>> L5 = 10;
>> Z = [L1+X;L5+X];
>> Z = Z(:)'
Z =
91 11 92 12 93 13 94 14
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