How to use the "parse" function to create optional function inputs

2017 2 5
2 个回答
回答已采纳
更新时间：2017 2 6
7 次查看（30 天）

0 个投票

Hello,
I am trying to use "parse" to create optional function inputs. Tried to replicate examples in the documentation (see below and attached) but I get the "too many arguments" error. Any idea? Thanks
my code below:
----------------
function []=testFun(A,varargList)
p = inputParser;
defaultNorm = 'L2';
validNorms = {'L1','L2'};
checkNorm = @(x) any(validatestring(x,validNorms));
addOptional(p,'lambda',0,@isnumeric)
addOptional(p,'norm',defaultNorm,checkNorm)
parse(A,varargList{:})
lambda = p.Results.lambda;
norm = p.Results.norm;
disp('input1 = ')
disp(A)
disp('lambda = ')
disp(lambda)
disp('norm = ')
disp (norm)
end

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 采纳的回答

Francois Steiner
Francois Steiner 2017-2-6

0 个投票

Hello,
I changed the name to varargin, but it still doesn't work, I have an error on the "parse" line. What am I missing?
See code below.
Thanks for your help.
François
function []=testFun(A,varargin)
p = inputParser;
defaultNorm = 'L2';
validNorms = {'L1','L2'};
checkNorm = @(x) any(validatestring(x,validNorms));
addOptional(p,'lambda',0,@isnumeric)
addOptional(p,'norm',defaultNorm,checkNorm)
parse(A,varargin{:})
lambda = p.Results.lambda;
norm = p.Results.norm;
disp('input1 = ')
disp(A)
disp('lambda = ')
disp(lambda)
disp('norm = ')
disp (norm)
end

4 个评论
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Walter Roberson
Walter Roberson 2017-2-6
You have to pass p as the first argument to parse
Francois Steiner
Francois Steiner 2017-2-6
It works! Thanks Walter for your patience.
Below corrected code in case it can be of help to anyone.
All the best,
François
function []=testFun(A,varargin)
p = inputParser;
defaultNorm = 'L2';
validNorms = {'L1','L2'};
checkNorm = @(x) any(validatestring(x,validNorms));
addRequired(p,'A',@ischar);
addOptional(p,'lambda',0,@isnumeric)
addOptional(p,'norm',defaultNorm,checkNorm)
parse(p,A,varargin{:})
lambda = p.Results.lambda;
norm = p.Results.norm;
disp('A = ')
disp(A)
disp('lambda = ')
disp(lambda)
disp('norm = ')
disp (norm)
end
Guillaume
Guillaume 2017-2-6
meta-comment: It's kind of bad form to accept your own answer to your own question, particularly as your answer is actually more of a comment on Walter's answer.
Walter Roberson
Walter Roberson 2017-2-6
Actually it is okay to accept your own Answer if you were the one who figured out the solution.

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更多回答（1 个）

Walter Roberson
Walter Roberson 2017-2-5

1 个投票

The variable name has to be varargin to be recognized as special, not varargList

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Francois Steiner
Francois Steiner 2017-2-6
编辑：Francois Steiner 2017-2-6
That simple - I thought any name would do. I really struggled with this one, many thanks for your help Walter, much appreciated. All the best, François

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