random Distribution Points inside rectangle
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hi every one how can i distribute randomly a number of points inside rectangle and every point has x,y ex: px(1)=100; py(1)=-100; and so forth where the rectangle code as shown bellow:-
x=-1100;
y=-1100;
rectangle('position',[x,y,2200,2200],'LineWidth',2,'LineStyle','--');
采纳的回答
Image Analyst
2017-2-5
Try this:
numPoints = 1000;
width = 2200;
x = -1100
y = -1100;
rectangle('Position', [x, y, width, width],'LineWidth',2,'LineStyle','--');
grid on;
xRandom = width * rand(1, numPoints) - width / 2;
yRandom = width * rand(1, numPoints) - width / 2;
hold on;
plot(xRandom, yRandom, 'r.', 'MarkerSize', 10);
title('Random Points Inside a Rectangle', 'FontSize', fontSize, 'Interpreter', 'None');
xlabel('X', 'FontSize', fontSize);
ylabel('Y', 'FontSize', fontSize);
axis equal;
% Put axis at origin
ax = gca;
ax.XAxisLocation = 'origin';
ax.YAxisLocation = 'origin';
% Set up figure properties:
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);
% Get rid of tool bar and pulldown menus that are along top of figure.
set(gcf, 'Toolbar', 'none', 'Menu', 'none');
% Give a name to the title bar.
set(gcf, 'Name', 'Demo by ImageAnalyst', 'NumberTitle', 'Off')
更多回答（1 个）
Bjorn Gustavsson
2017-2-5
1 个投票
Have a look at the documentation of rand. That function gives you uniformly distributed random numbers between 0 and 1 (have forgotten about what the limits are, but you'll see). Then think about what happens if you add and multiply those numbers with some fixed constants, then think about what happens if you combine 2 such numbers into a 2-d vector. If you want some other distribution of the points inside your rectangle or want the points to have some covariance structure you'll have to work those out as well.
HTH
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