How to break a code when conditions are met

2 次查看（过去 30 天）
DIP
DIP 2017-2-8
评论： DIP 2017-2-8
So I have a code with 2 numerical methods - backward euler and Runge kutta. What I want to do is create a program that calculates both numerical methods for a simple ODE and then stops when the difference between the two methods is 10e-5. The RK method is set for 11 iterations. The backward euler should end at approx 7380 iterations. How can this be done ?

请先登录，再回答此问题。

回答（1 个）

KSSV
KSSV 2017-2-8
编辑：KSSV 2017-2-8
doc break
for i = 1:100
if i==7 % a condition
disp('I am exiting')
break
end
end
  3 个评论
显示 1更早的评论
DIP
DIP 2017-2-8
unfortunately it did not. The ODE is dC/dx=C*S/U .

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Runge Kutta Methods 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by