access multidimensional array per row

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Joyce Shin
Joyce Shin 2017-2-9
评论： Joyce Shin 2017-2-10
Hi,
I have 10x1 cell named Results in which includes 672x7 cell in each cell. For 672x7 cell, I want to access row by row. However, it throws an error saying "Index exceeds matrix dimensions." Can you see which line is a problem?
for i1=1:size(Results,1) % 10*1 cell
for i2=1:size(Results{i1,1}) % 672*7 cell
for i3=1:size(tc,2) % 7 methods
min(Results{i1,i2}(i3,:))
end
end
end

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回答（1 个）

James Tursa
James Tursa 2017-2-9
编辑：James Tursa 2017-2-9
i2 ranges from 1 to 1st dimension of Results{i1}, which is 672. You can't then turn around and use this as the 2nd index in Results. I.e., Results{i1,i2} can't use i2 in that 2nd index since that dimension only goes up to 1. So you need to rethink and redo that Results{i1,i2}(i3,:) reference. It's going to have to look like Results{i1}{i2,something}etc.
Also, your for loops have size(something) as an upper limit, but size returns a vector. Do you really want to use numel(something) or size(something,1) instead?
  2 个评论
Joyce Shin
Joyce Shin 2017-2-10
Hi, Thanks for the comment. If I modify my code this way, it works. I removed i3, since I already know the range.
Results{i1}(i2,1:7)
Joyce Shin
Joyce Shin 2017-2-10
And can you suggest any other way other than size() to get array size?

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