Solving non linear equation for a constant

1 次查看(过去 30 天)
I have got(after writing some code) 1) y = A1/2 - (A1*exp(-(2*t)/3))/2 and yred = exp(-2*t)/2 - exp(-t) + 1/2. I need to equate the constants and find A1. It is possible that there might be some other y and yred if some other inputs are given by users.As an example here A1/2 = 1/2, therefore A1= 1. So in in any case I need to equate the 2 constants in these two equations. How should I do it. Note that even approximate answers(like A1 = 0.99 instead of 1) are fine with me. I can think of two approaches, one either separate the constants somehow and equate them or take large t for eg 10000 and then equate both equations, that will also give almost exact A1. How should I translate any of the approach into matlab. Or in other words, how should I solve the above problem

采纳的回答

Torsten
Torsten 2017-2-10
syms A t
y = A/2-(A*exp(-(2*t)/3))/2;
z = exp(-2*t)/2-exp(-t)+1/2;
eqn = limit(y,t,inf)==limit(z,t,inf);
solA = solve(eqn,A);
Best wishes
Torsten.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Calculus 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by