Changing the dimensions of a variable.

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Alexandra Ridgway
Alexandra Ridgway 2017-2-12
评论： Alexandra Ridgway 2017-2-12
Hi,
Fe68 has dimensions 151x31. AnomFe68, once I've done the following, has dimensions 1x4429. I want it to have the same dimensions as Fe68 but replacing the numbers with 1/0 as directed. I believe if I achieve this then the line 'finalFe68 = anomFe68*dz(:)*dlong' will stop giving me the error 'inner matrix dimensions must agree'?
Please advise.
dlong = 109079.92
anomFe68(Fe68<=0)=0
anomFe68(Fe68>0)=1
for j=2:31
dz(j)=abs(depth(j)-depth(j-1))
end
finalFe68 = anomFe68*dz(:)*dlong
sum(final68)
Thank you,
Alexandra

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回答（1 个）

Jan
Jan 2017-2-12
编辑：Jan 2017-2-12
Perhaps you want:
anomFe68 = double(Fe68 > 0);
Note that this treats the line "anomFe68(Fe>0)=1" as it is "anomFe68(Fe68>0)=1" .

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