How do I find the base of a right angle triangle b=xcos(a) in matlab.

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Julie Wanjiru
Julie Wanjiru 2017-2-15
评论： Walter Roberson 2017-3-26
('x' has to be a positive value and 'a' has to entered in degrees then converted to radian)

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回答（1 个）

Andres Yie
Andres Yie 2017-3-26
Use the comands:
a = input('Enter a in radians')
x = input('Enter x')
a = rad2deg(a) %Converts to degrees
b = x*cosd(a);
Also you can skip the radinas and use the cos() function that accepts the argument in radians.

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