Convert multi dimensional array to a matrix

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Let's say I have A = rand(2,2,2,2). Considering the last two index of the Array A(2,2,x,x) as positions in a matrix such that Matrix(1,1) = A(2,2,1,1) Matrix(1,2) = A(2,2,1,2)..... and so forth.
Ultimately I will end up with a 4,4 matrix in this case.
How can I do this without writing a loop. Please advise.
Update:
I think my question didn't come through correctly. I apologize for it.
Let's have
A(:,:,1,1) =
0.1455 0.8693
0.1361 0.5797
A(:,:,2,1) =
0.5499 0.8530
0.1450 0.6221
A(:,:,1,2) =
0.3510 0.4018
0.5132 0.0760
A(:,:,2,2) =
0.2399 0.1839
0.1233 0.2400
Now I want to have a new Matrix such that
1 2
1 M = [M11 M12;
2 M21 M22];
In my M11 I want A(:,:,1,1)
In my M12 I want A(:,:,1,2) and so forth.
Ultimately I have a 4X4 matrix.
Does it make sense?
Thank you

回答(1 个)

Walter Roberson
Walter Roberson 2017-2-17
squeeze(A(2, 2, :, :))
  6 个评论
Arif Ahmed
Arif Ahmed 2017-2-18
编辑:Arif Ahmed 2017-2-18
Yes. This is what I meant.
Yes, I agree it doesn't agree with my original post. I was thinking of including 2x2 matrix somehow it translated into (2,2,x,x) in writing. I apologize.
shaziah A
shaziah A 2018-8-7
Did you have chance to put them into a matrix? I am also trying to do the same and would really appreciate some help.

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