How can I plot a graph for only one eigen value against a variable? I'm only getting one M!
显示 更早的评论
I am trying to plot a graph for k:[0,1] against the larger eigenvalue from the corresponding matrix. i.e for each value of k I am only interested in the larger of the two eigenvalues from the 2x2 matrix M.
This is a very basic code, I know, but having played around with it for a few days now I could really use some help!
% code
A=3.3;
B=0.45;
a=B;
b=((A+sqrt(A^2-4*B^2))/(2*B))^2;
c=-2*B;
d=-1-b;
D=500;
for k=0.0:0.01:1.0
M=[a-k^2 b; c d-D*k^2];
lam=eig(M);
end
plot(k,lam)
end
采纳的回答
Akira Agata
2017-2-17
编辑：Akira Agata
2017-2-17
I have slightly modified your code. I hope this will help!
A=3.3;
B=0.45;
a=B;
b=((A+sqrt(A^2-4*B^2))/(2*B))^2;
c=-2*B;
d=-1-b;
D=500;
k = (0:0.01:1);
lam = zeros(2,length(k));
for kk = 1:length(k)
M=[a-k(kk)^2 b; c d-D*k(kk)^2];
lam(:,kk)=eig(M);
end
plot(k,lam)
3 个评论
Jessica Wilcox
2017-2-17
Akira Agata
2017-2-17
Yes, that's a piece of cake!
Let me slightly modify the code again.
A=3.3;
B=0.45;
a=B;
b=((A+sqrt(A^2-4*B^2))/(2*B))^2;
c=-2*B;
d=-1-b;
D=500;
k = (0:0.01:1);
lam = zeros(1,length(k));
for kk = 1:length(k)
M=[a-k(kk)^2 b; c d-D*k(kk)^2];
lam(kk)=max(eig(M));
end
plot(k,lam)
Now, you can obtain a plot only the larger eigenvalue as a function of k.
Jessica Wilcox
2017-2-23
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