Set of indexes to vector without loop?

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Kamil Antos
Kamil Antos 2017-2-17
编辑： Guillaume 2017-2-17
Hi, the problem is as follow:
There is matrix with indexes:
IND =
1 15
26 40
51 65
I would like to create vector which looks like:
VEC = [1,2,...14,15,26,27,...39,40,51,52...64,65]
For that specific example answer is:
VEC = [1:15, 26:40, 51:65]
but I would like to find general solution without looping. It should be independent from number of rows in in IND.
I didn't find any solution in Matlab answers but I am sure that is possible.
Any ideas? Best Kamil

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采纳的回答

Guillaume
Guillaume 2017-2-17
编辑：Guillaume 2017-2-17
A for loop as per KSSV's answer is probably the best way to do this.
cell2mat(arrayfun(@(s,e) s:e, IND(:, 1), IND(:, 2), 'UniformOutput', false)')
would be one way to do it without a loop, if you consider arrayfun not to be a loop. It's more likely to be slower than an actual for loop.
See also my old cody problem which asks to do just the same. For information, the best scoring solution is:
str2num(sprintf('%d:%d ', IND'))
whose only merit is that it is low scoring on cody. Certainly don't use that for real code, it's going to be very slow.

更多回答（1 个）

KSSV
KSSV 2017-2-17
iwant = [] ;
for i = 1:size(IND,1)
iwant = [iwant IND(i,1):IND(i,2)] ;
end
A more elegant solution might be possible.

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