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problems using newtons method

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justin simmons
justin simmons 2017-2-19
编辑： justin simmons 2017-2-19
x = -2;
Tol = 0.0000001;
count = 0;
dx=1;
f=-13;
fprintf('step x dx f(x)\n')
fprintf('---- ----------- --------- ----------\n')
fprintf('%3i %12.8f %12.8f %12.8f\n',count,x,dx,f)
xVec=x;fVec=f;
while (dx > Tol || abs(f)>Tol)
count = count + 1;
fprime = cosx-x;
xnew = x - (f/fprime);
dx=abs(x-xnew);
x = xnew;
f = cosx-x;
fprintf('%3i %12.8f %12.8f %12.8f\n',count,x,dx,f)
end
this is what i was have. how can i fix this?

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回答（1 个）

Walter Roberson
Walter Roberson 2017-2-19
You could define cox and cost

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