problems using newtons method

2017 2 19
1 个回答
更新时间：2017 2 19
2 次查看（30 天）

0 个投票

x = -2;
Tol = 0.0000001;
count = 0;
dx=1;
f=-13;
fprintf('step x dx f(x)\n')
fprintf('---- ----------- --------- ----------\n')
fprintf('%3i %12.8f %12.8f %12.8f\n',count,x,dx,f)
xVec=x;fVec=f;
while (dx > Tol || abs(f)>Tol)
count = count + 1;
fprime = cosx-x;
xnew = x - (f/fprime);
dx=abs(x-xnew);
x = xnew;
f = cosx-x;
fprintf('%3i %12.8f %12.8f %12.8f\n',count,x,dx,f)
end
this is what i was have. how can i fix this?

请先登录，再回答此问题。

回答（1 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Startup and Shutdown 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by