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delete rows from cell array

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Elysi Cochin
Elysi Cochin 2017-2-23
编辑： Guillaume 2017-2-23
i have a cell array with string as below (format is "number""space""-""space""number")
1234 - 5678
543 - 2345
5678 - 1234
delete the numbers relations such as
1234 - 5678
5678 - 1234
and keep first one of them and get output as
1234 - 5678
543 - 2345
i need to search using '-'
i get empty matrix, when i do as below
index = find(ismember(cellArr(1), ' - '))
  2 个评论
Rik
Rik 2017-2-23
So your question is how to remove the rows with pairs that are descending?
index is empty, because you are comparing a single cell with the text ' - '. I think you should take a look at strfind.
Adam
Adam 2017-2-23
You say you want to delete numbers, but then give an example output which still contains the same first line as I thought you wanted to delete?

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采纳的回答

Guillaume
Guillaume 2017-2-23
编辑：Guillaume 2017-2-23
I'm assuming that you want to delete repeated pairs regardless of the order the numbers appear in the pair.
Possibly the easiest way would be:
c = {'1234 - 5678';
'543 - 2345';
'5678 - 1234';}
[~, urows] = unique(regexprep(c, '([^- ]*) - ([^-]*)', '${strjoin(sort({$1, $2}), '' - '')}'), 'stable');
filteredc = c(urows)

更多回答（1 个）

Pooja Patel
Pooja Patel 2017-2-23
A(1:2)={rand(10,6)}
A =
[10x6 double] [10x6 double]
>> row=2; A{1}(2,:)=[] %delete 1 row from 1 cell
A =
[9x6 double] [10x6 double]

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