delete rows from cell array
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i have a cell array with string as below (format is "number""space""-""space""number")
1234 - 5678
543 - 2345
5678 - 1234
delete the numbers relations such as
1234 - 5678
5678 - 1234
and keep first one of them and get output as
1234 - 5678
543 - 2345
i need to search using '-'
i get empty matrix, when i do as below
index = find(ismember(cellArr(1), ' - '))
2 个评论
Rik
2017-2-23
So your question is how to remove the rows with pairs that are descending?
index is empty, because you are comparing a single cell with the text ' - '. I think you should take a look at strfind.
Adam
2017-2-23
You say you want to delete numbers, but then give an example output which still contains the same first line as I thought you wanted to delete?
采纳的回答
I'm assuming that you want to delete repeated pairs regardless of the order the numbers appear in the pair.
Possibly the easiest way would be:
c = {'1234 - 5678';
'543 - 2345';
'5678 - 1234';}
[~, urows] = unique(regexprep(c, '([^- ]*) - ([^-]*)', '${strjoin(sort({$1, $2}), '' - '')}'), 'stable');
filteredc = c(urows)
更多回答（1 个）
Pooja Patel
2017-2-23
A(1:2)={rand(10,6)}
A =
[10x6 double] [10x6 double]
>> row=2; A{1}(2,:)=[] %delete 1 row from 1 cell
A =
[9x6 double] [10x6 double]
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