Hi Haroon
it does return the unique values sorted out, but what perhaps confuses you is the amount of output arguments you are using:
1.
unique returns up to 3 values
A=[4 4 3 -1 -1 10 10]
[L,ni,nj]=unique([4 4 3 -1 -1 10 10])
L =
-1 3 4 10
ni =
4
3
1
6
nj =
3
3
2
1
1
4
4
where A(ni) and L are the same
A(ni)
=
-1 3 4 10
isequal(L,A(ni))
=
1
and L(nj)=A
2. if you only take 2 outputs, only the positions of the 1st found unique values are returned, along with the unique values
[L,ni]=unique([4 4 3 -1 -1 10 10])
L =
-1 3 4 10
ni =
4
3
1
6
3. with only one output variable, there are not indices, just the 1st-found unique values
unique([4 4 3 -1 -1 10 10])
=
-1 3 4 10
so the progressive numerals you mention are actually the indices of the unique values found, since there are no repeated values, you see the progressive indices as found along th vector.
Check the output variables of the unique you are using and make sure values and indices are not crossed.
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thanks in advance
John BG
