help with nested loops error

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Roger Vota
Roger Vota 2017-3-4
回答： Guillaume 2017-3-7
Somehow only first step in a loop is executed:
spiketime = (1:3:100);
stim = (1:10:100);
for i=1:size(stim);
for t = 1:size(spiketime);
if abs(spiketime(t)-stim(i)) < 3;
spiketime(t) = [];
end
end
end
What am I missing?

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采纳的回答

Guillaume
Guillaume 2017-3-7
"Thank you very much, it works now!"
Well, after a fashion, it will have got rid of one error, but the code definitively won't work as you want. Deleting elements while you're looping over them never works: your loop index will get out of sync with the content of the array.
In any case, a loop is not needed:
spiketime = 1:3:100; %() brackets unneeded, just add noise
stim = 1:10:100
%in R2016b:
spiketime(any(abs(spiketime - stim.') < 3)) = [];
%in versions prior to R2016b
spiketime(any(abs(bsxfun(@minus, spiketime, stim')) < 3)) = [];

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