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3D Matrix to 2D Matrix

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Adan91h
Adan91h 2017-3-4
评论： Star Strider 2017-3-4
I have four 3D matrix like Y= ones(2,2,4) and i want to make a new matrix like YT=zeros(8,8).
I want to take values from 3D "Y" matrix and insert them into 2D "YT" matrix in a following fashion
YT(1,1)=Y(1,1,1)
YT(1,2)=Y(1,2,1)
YT(2,1)=Y(2,1,1)
YT(2,2)=Y(2,2,1)
YT(3,3)=Y(1,1,2)
YT(3,4)=Y(1,2,2)
YT(4,3)=Y(2,1,2)
YT(4,4)=Y(2,2,2)
YT(5,5)=Y(1,1,3)
YT(5,6)=Y(1,2,3)
YT(6,5)=Y(2,1,3)
YT(6,6)=Y(2,2,3)
YT(7,7)=Y(1,1,4)
YT(7,8)=Y(1,2,4)
YT(8,7)=Y(2,1,4)
YT(8,8)=Y(2,2,4)
Can some one suggest me what would be the best way to do this thing automatically? I only assume the values of Y to 1,1,1,1 but in my real case, values of Y are different complex numbers.

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采纳的回答

Star Strider
Star Strider 2017-3-4
编辑：Star Strider 2017-3-4
This works:
y = 1:16; % Create Data
Y = reshape(y, 2, 2, 4); % Create Data
RY = reshape(Y(:), 2, []); % Reshape ‘Y’
RC = mat2cell(RY, 2, ones(1,size(RY,2)/2)*2); % Create Submatrices
YT = blkdiag(RC{:}) % Create ‘YT’
  4 个评论
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Adan91h
Adan91h 2017-3-4
Thanks once again :). Now its working perfectly. You are great!!!
BR, Adnan
Star Strider
Star Strider 2017-3-4
My pleasure! Thank you for your compliment!
(I apologize for the earlier confusion. I’m UTC-7 here, and wasn’t fully awake then.)

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更多回答（1 个）

John BG
John BG 2017-3-4
编辑：John BG 2017-3-4
Hi Adnan
1.
generating test matrices
Y=randi([-10 10],2,2,4)
YT=zeros(8,8)
YT([1 2],[1 2])=Y(:,:,1)
YT([3 4],[1 2])=Y(:,:,2)
YT([5 6],[1 2])=Y(:,:,3)
2. moving values
[sz1 sz2 sz3]=size(Y)
for k=1:1:sz3
YT([2*k-1 2*k],[2*k-1 2*k])=Y(:,:,k)
end
3. the values of Y and YT can be complex, there's no need to build 2 matrices containing real and imaginary parts.
if you find this answer useful would you please be so kind to mark my answer as Accepted Answer?
To any other reader, please if you find this answer of any help solving your question,
please click on the thumbs-up vote link,
thanks in advance
John BG
<mailto:jgb2012@sky.com jgb2012@sky.com>

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