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Hello i want to know if exist a function that generate numbers in a range that i want to fix. for example i need to generate 22 numbers in this range: 0.5000 and 0.600
can you help me? thank you
回答（2 个）
Aldin
2012-3-20
Here:
0.5:0.1/20:0.6
Beacuase: (0.6 - 0.5)/20
5 个评论
Oleg Komarov
2012-3-20
Actually it's:
a = 0.5:0.1/21:0.6;
Alternatively a high level function (which uses the engine showed by Aldin)
b = linspace(.5,.6,22);
Geoff
2012-3-20
Using linspace to generate a series is preferable here because it has more transparent semantics. _ie_ "I want 22 values between A and B". It's also easier to change the range without introducing errors. What if you decided you needed to go between 0.5 and 0.7? How will you make sure you don't make a mistake with the colon operator?
Aldin
2012-3-20
Hi Oleg, when yout write 0.1/21 the length of the vector is 23 not 22
Oleg Komarov
2012-3-20
In my case is 22.
Geoff
2012-3-20
Oleg is correct: length( 0.5:0.1/20:0.6 ) is 21. You really should use linspace if you want a linear sequence with a specified number of elements. That's what it's there for.
Geoff
2012-3-20
You haven't really specified if you want a sequence or just a set of numbers. Picking up on your term 'generate', perhaps you meant this:
randarr = @(lo, hi, n) lo + (hi-lo) * rand(1,n);
data = randarr(0.5, 0.6, 22);
That creates a bunch of random numbers in your specified range. Note I've wrapped it in an anonymous function to give the same syntax as linspace.
1 个评论
Geoff
2012-3-20
Oops, just realised I specified that anonymous function incorrectly. Fixed.
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2012-3-20
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