Can I define variable in matlab?

5 次查看（过去 30 天）
kritika adhikari
kritika adhikari 2017-3-13
评论： kritika adhikari 2017-3-18
Do we need any particular command if i need variable. If A=[1 2 3] i need this as: A=[X1 X2 X3]
  8 个评论
显示 6更早的评论
kritika adhikari
kritika adhikari 2017-3-14
Actually m designing an interleaver. So what I need is to pass the blocks of message. That messages are in variable form . The interleaver will be constructed in such a way that the messages that has been passed will appear in matrix form with variables but not with binary digits.
Walter Roberson
Walter Roberson 2017-3-14
Well, then what I posted will allow you to do that. You should go ahead and try and see if it works for your needs.
I think you are making a mistake, though. The output from an interleaver would normally be symbols, not variables. For practical purposes, the symbols would normally be encoded as non-negative integers that could be used as indices.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2017-3-14
int_data=[4 2 1 5 6 3]
X = sym('X', [1, max(int_data)]);
y = X(int_data);
The result would be
y = [X4 X2 X1 X5 X6 X3]
  1 个评论
kritika adhikari
kritika adhikari 2017-3-18
Yeah I got It. Actually you were right. The output from interleaver are not variables. Thank you so much.

请先登录，再进行评论。

更多回答（1 个）

ES
ES 2017-3-14
编辑：ES 2017-3-14
From what I understand from your code, you can simply put
y = X (int_data);
[ Example:
X = [2,4,6,8,10,12,14,16,18]
int_data=[4 2 1 5 6 3];
disp(X(int_data));
>> 8 4 2 10 12 6
]
If this is not what you need, Please say what are your inputs and outputs? The code you have provided is not enough!

类别

在 Help Center 和 File Exchange 中查找有关 Whos 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by