str2func vectorize input x1, x2 to x
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When using str2func, I find that I can do these things such as,
str = 'x(1)^2 + 3*x(2)';
f = str2func(['@(x)' str]);
f([4 5])
and
str1 = 'x + 2*u';
f1 = str2func(['@(x,u)' str1]);
f1(2,3)
However, what I need is something like
str2 = 'x(1) + u - x(2)';
f2 = str2func('@(x,u)', str2);
f2([1,2],3)
which gives me an error "Too many input arguments."
Any suggestions please? Thank you all in advance.
Qun
采纳的回答
dpb
2017-3-16
You didn't follow your previous successful pattern...
f1 = str2func(['@(x,u)' str1]);
as written is the concatenation of two strings; you correctly concatenated the argument list to the function in the previous cases but for some reason didn't for the following...
f2 = str2func('@(x,u)', str2);
Simply write like you did f1
f2 = str2func(['@(x,u)' str2]);
and all is well. The error is there were two instead of only one string in the argument list.
更多回答（2 个）
Hi Qun Wu
with the following syntax it works ok
str2 = 'x1 + u - x2'; f2 = str2func(['@(x1,x2,u)', str2]); f2(1,2,3)
the following also works ok
str2 = 'x(1) + u - x(2)'; f2 = str2func(['@(x,u)', str2]);f2([1 2],3)
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John BG
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