How can I output my answer automatically with different sub-folders?

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Let say, now, I need to read AndroidManifest.xml, and I have n folders to undergo, namely M1, M2, M3... Mn. Is there a way to make it examine automatically? So my output will contain a feature vector from different folders.
Below is my sample code:
text1 = fileread('C:\Users\ASUS\Desktop\FYP\ *M1*\AndroidManifest.xml'); % read input manifest file
text2 = regexp(fileread('Dataset1_Permission.txt'), '\r?\n', 'split'); % read android permission list dataset
matchStr = regexp(text1,'\"android.permission.\w*\"','match'); %extract the keyword in manifest file
features1 = ~cellfun(@isempty,regexp(text1,text2));
disp(matchStr);
  2 个评论
ai ping Ng
ai ping Ng 2017-3-17
As stated above, I can't figure out how to output my answer when I have more than 1 folder to examine. Now it's fine since I only examine M1 folder only, but instead of manually changing my directory to M2, M3, and so on... is there a way to read it automatically by using Matlab?

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采纳的回答

Rik
Rik 2017-3-17
Have you tried a loop the filename formed with sprintf?
for folder_number=1:5
text1 = fileread(sprintf('C:\Users\ASUS\Desktop\FYP\M%d\AndroidManifest.xml',folder_number)); % read input manifest file
text2 = regexp(fileread('Dataset1_Permission.txt'), '\r?\n', 'split'); % read android permission list dataset
matchStr = regexp(text1,'\"android.permission.\w*\"','match'); %extract the keyword in manifest file
features{folder_number} = ~cellfun(@isempty,regexp(text1,text2));
disp(matchStr);
end
I don't know what you would want to do with matchStr. (Note: if you have many folders, pre-allocating the features variable may be a good idea)
  6 个评论
Rik
Rik 2017-3-17
You mean something like
%answer = [1x137 logical] [1x137 logical] [1x137 logical]
for item=1:length(answer)
answer{item}=answer{item}';
end
answer = cell2mat(answer);
(just an off the cuff answer, plus I'm tired, so no guarantees)
Guillaume
Guillaume 2017-3-17
Note: the reason for the Warning: Control Character '\U' is not valid is because the '\' used as path separator here has special meaning in sprintf. It introduces control characters. If you want the '\' to be interpreted as such, you need to escape it by doubling it.
sprintf('C:\\Users\\ASUS\\Desktop\\FYP\\M%d\\AndroidManifest.xml')
would have worked. But as Rik said, Windows doesn't mind '/' as a path separator, so you may use that as well.

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更多回答(1 个)

Walter Roberson
Walter Roberson 2017-3-17
https://www.mathworks.com/matlabcentral/answers/57446-faq-how-can-i-process-a-sequence-of-files

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