find the histogram of the image(cameraman)without using the matlab built-in functions for histogram calculations.compare your result with the with those obtained using the functions imhist().display the input image,the two histograms-(yours and matla

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if true
% code
end

采纳的回答

Marwa Ahmeid
Marwa Ahmeid 2017-3-20
编辑:Marwa Ahmeid 2017-3-20
%By Marwa Ahmeid
function [y]=myimhist(img)
[r,c]=size(img);
y=zeros(1,256);
for i=1:r
for j=1:c
z=img(i,j);
y(z+1)=y(z+1)+1;
end
end

更多回答(3 个)

Image Analyst
Image Analyst 2017-3-17
The code you posted won't do it obviously. You need to use a for loop over all rows and all columns. The gray level will be the index of a "counts" array that you'll build up. Hint:
[rows, columns, numberOfColorChannels] = size(grayImage);
counts = zeros(1, 256);
for col = 1 : columns
for row = 1 : rows
  7 个评论
Image Analyst
Image Analyst 2020-4-9
Looks like I said to add 1 in the comment but didn't in the code. Thanks for catching that. Here is corrected code:
function [counts, grayLevels] = MyHistogram(grayImage)
[rows, columns, numberOfColorChannels] = size(grayImage);
counts = zeros(1, 256);
for col = 1 : columns
for row = 1 : rows
% Get the gray level.
grayLevel = grayImage(row, col);
% Add 1 because graylevel zero goes into index 1 and so on.
counts(grayLevel+ 1) = counts(grayLevel+1) + 1;
end
end
% Plot the histogram.
grayLevels = 0 : 255;
bar(grayLevels, counts, 'BarWidth', 1, 'FaceColor', 'b');
xlabel('Gray Level', 'FontSize', 20);
ylabel('Pixel Count', 'FontSize', 20);
title('Histogram', 'FontSize', 20);
grid on;
end

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T G
T G 2018-12-11
Thank u so much Image Analyst for helping..

Ankan Banerjee
Ankan Banerjee 2021-9-19
Can histogram be calculated using find() command?
  1 个评论
Image Analyst
Image Analyst 2021-9-19
Yes, if you used a loop to find all the values that fell in a certain range and then sum them up into the appropriate bin, but why would you want to do it that more complicated way?

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