Translate a matrix with nested loops?

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Colin Starker
Colin Starker 2017-3-18
回答： dpb 2017-3-18
I need to translate a matrix up and to the right with nested loops.
The code should be able to take any matrix A...
A=
[1 2 3 4 5;
6 7 8 9 10;
11 12 13 14 15;
16 17 18 19 20]
...and translate it by user inputs X and Y (2 and 2, in this example) to produce matrix B...
B=
[0 0 11 12 13;
0 0 16 17 18;
0 0 0 0 0;
0 0 0 0 0]

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采纳的回答

Roger Stafford
Roger Stafford 2017-3-18
No need for loops:
up = 2; right = 2;
B = zeros(size(A));
B(1:end-up,1+right:end) = A(1+up:end,1:end-right);

更多回答（1 个）

dpb
dpb 2017-3-18
Alternate
B=circshift(A,[up right]);
B(:,1:right)=0; B(end-up+1:end,:)=0;
I've always thought there should be a companion to cirshift that shifts in a constant or by default zero...think I've made the enhancement request a time or two, even.

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