cannot call or index into a temporary array

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VAIDEKH RAJENDRAN SALEEMA
编辑： Walter Roberson 2017-3-19
for i=1:L-1 nr(i,:)=sqrt(n/2){randn(1,1000)+sqrt(-1)*randn(1,1000)}; end
this is my code and showing the error on call index nto a temporary array

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回答（1 个）

GEEVARGHESE TITUS
GEEVARGHESE TITUS 2017-3-19
Though your question is not clear, on what your requirement is, I have a made a change that computes the value nr
L=10;
n=10;
for i=1:L-1
nr(i,:)=sqrt(n/2).*(randn(1,1000)+sqrt(-1)*randn(1,1000));
end
When you are using curly brackets it means that you are planning to access a cell given by an index, for example c{1} or can be c{i}.

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