divide and conquer
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please
anyone can give me source code about divide and conquer method
thank you
2 个评论
Oleg Komarov
2012-3-25
Being "an algorithm design paradigm" there's no specific source code for it: http://en.wikipedia.org/wiki/Divide_and_conquer_algorithm
Also, additional info could give contributors a chance of answering:
http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer
回答(1 个)
Walter Roberson
2012-3-25
Certainly. In order for this to be a proper "divide and conquer" source contribution, each of the readers of this site will contribute part of the source, and it will be up to you to put everything together.
My contribution to your D&Q source follows on the next line:
=
Hope that helps!
4 个评论
Walter Roberson
2017-5-22
Peter Weigel comments to Walter Roberson:
This comment is detrimental to the health of the MathWorks forums.
Walter Roberson
2017-5-22
Peter Weigel: the MathWorks forums seem to have thrived in the five years since I posted that response to someone who asked a vague question and expected to be given full source without any effort on their part.
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