why color fringes are not deformed by peak function?

2 次查看（过去 30 天）

ajeet verma 2017-3-27

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/332075-why-color-fringes-are-not-deformed-by-peak-function

评论： KSSV 2017-3-27

i have a code in which fringe pattern is projected on the 3D object(peaks) and fringes are deformed according to peaks. code is--

m=1000;
n=1000;
%object
[x,y,z]=peaks;
z=imresize(z,[m,n]);
Q=exp(1i*z*1);
subplot(2,3,1),imshow(z,[])
%sinusoidal fringes
f1=30;
f2=0;
for i = 1:m
for j=1:n
a(i,j)=exp(1i*2*pi*(f1*j/n+f2*i/m));
end
end
V=128*(real(a)+1);
subplot(2,3,2),imshow(V,[])
%modulation
U=128*(real(a.*Q)+1);
subplot(2,3,3),imshow(U,[])
   but when color fringe patterns are projected, these are not deformed but i need . code is given 
  %color fringe projection
  m=1000;
  n=1000;
  % object
  [x,y,z]=peaks;
  z=imresize(z,[m,n]);
  Q=exp(1i*z*2);
  subplot(331),imshow(z,[]),impixelinfo;
  % color fringes
  f1=20;                              % No. of vertical fringes
  f2=0;                               % No. of horizontal fringes
  a1 = zeros(m,n) ;
  a2 = zeros(m,n) ;
  a3 = zeros(m,n) ;
  for i=1:m
  for j=1:n
  a1(i,j)=exp(1i*(2*pi*(f1*j/n+f2*i/m)-2*pi/3));
  a2(i,j)=exp(1i*(2*pi*(f1*j/n+f2*i/m)));
  a3(i,j)=exp(1i*(2*pi*(f1*j/n+f2*i/m)+2*pi/3));
  end
  end
  Color=zeros(m,n,3);
  Color(:,:,1)=a1;
  Color(:,:,2)=a2;
  Color(:,:,3)=a3;
  %imshow(Color,[]),impixelinfo;
  imwrite(Color,'myimage1.jpg');
  % seperation into r,g,b component
  i = imread('myimage1.jpg'); % Read image
  red = double(i(:,:,1)); % Red channel
  green = double(i(:,:,2)); % Green channel
  blue = double(i(:,:,3)); % Blue channel
  %a = zeros(size(i, 1), size(i, 2));
  %R = cat(3, red, a, a);
  %G = cat(3, a, green, a);
  %B = cat(3, a, a, blue);
  subplot(332),imshow(red,[]);
  subplot(333),imshow(green,[]);
  subplot(334),imshow(blue,[]);
  % projection 
  R=real(red.*Q);
  G=real(green.*Q);
  B=real(blue.*Q);
  subplot(335),imshow(R,[]);
  subplot(336),imshow(G,[]);
  subplot(337),imshow(B,[]);