why the conv(u,v,'same') choose the a vector a little right deviated to center position
1 次查看(过去 30 天)
显示 更早的评论
For example
>> a=[1:10];
>> b=[7:7:28];
>> conv(a,b)
ans =
7 28 70 140 210 280 350 420 490 560 553 462 280
>>conv(a,b,'same')
ans =
70 140 210 280 350 420 490 560 553 462
The same option give a vector vector from element 70. Why not from element 28? Are there any math/enginerr reasons?
0 个评论
采纳的回答
Greg Dionne
2017-3-30
If b is of odd length, you will obtain what you expect.
For even length it will move to the next available point having the gap at the beginning, not at the end. To get the other way, try:
>> fliplr(conv(fliplr(a),fliplr(b),'same'))
ans =
28 70 140 210 280 350 420 490 560 553
3 个评论
Image Analyst
2017-3-30
Basically it's shifted a half element to the side if you're using an even number of elements in your scanning kernel window instead of an odd number.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Spectral Estimation 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!