Print a table with 4 columns fprintf

95.0000 1.8700 10.9831 8.9874
2.0000 45.0000 1.6000 7.1402
3.0000 76.0000 1.7000 9.3224
4.0000 88.0000 1.6100 9.5381
5.0000 55.0000 1.5000 7.4204
6.0000 50.0000 1.6100 7.5010
7.0000 61.0000 1.5800 8.0519
8.0000 105.0000 1.8300 11.2821
I specify the vectors like this: N=[1,2,3,4,5,6,7,8]; and I use fprintf(fileID,'%5.2f\n\' but if i repeat this for my other variable it all ends up in one column?How to get it in 4 columns

回答(2 个)

A = magic(5) ;
fprintf([repmat('%f\t', 1, size(A, 2)) '\n'], A')

1 个评论

Note that transpose A.' should be used, and not conjugate transpose A'.

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When you put all of the data into one matrix then your task is easy:
>> M = [95, 1, 10.9831, 8.9874;...
2, 45, 1.6000, 7.1402;...
3, 76, 1.7000, 9.3224;...
4, 88, 1.6100, 9.5381;...
5, 55, 1.5000, 7.4204;...
6, 50, 1.6100, 7.5010;...
7, 61, 1.5800, 8.0519;...
8, 105, 1.8300, 11.2821];
>> fmt = '%3d,%4d,%6.2f,%6.2f\n';
>> fprintf(fmt,M.')
95, 1, 10.98, 8.99
2, 45, 1.60, 7.14
3, 76, 1.70, 9.32
4, 88, 1.61, 9.54
5, 55, 1.50, 7.42
6, 50, 1.61, 7.50
7, 61, 1.58, 8.05
8, 105, 1.83, 11.28
Note that I specified different formats for each column, and used transpose M.' instead of the linear algebra operation ctranspose M'.

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