Print a table with 4 columns fprintf

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Sook Yee Lim
Sook Yee Lim 2017-3-31
编辑： Stephen23 2017-3-31
95.0000 1.8700 10.9831 8.9874
2.0000 45.0000 1.6000 7.1402
3.0000 76.0000 1.7000 9.3224
4.0000 88.0000 1.6100 9.5381
5.0000 55.0000 1.5000 7.4204
6.0000 50.0000 1.6100 7.5010
7.0000 61.0000 1.5800 8.0519
8.0000 105.0000 1.8300 11.2821
I specify the vectors like this: N=[1,2,3,4,5,6,7,8]; and I use fprintf(fileID,'%5.2f\n\' but if i repeat this for my other variable it all ends up in one column?How to get it in 4 columns

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回答（2 个）

KSSV
KSSV 2017-3-31
A = magic(5) ;
fprintf([repmat('%f\t', 1, size(A, 2)) '\n'], A')
  1 个评论
Stephen23
Stephen23 2017-3-31
Note that transpose A.' should be used, and not conjugate transpose A'.

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Stephen23
Stephen23 2017-3-31
编辑：Stephen23 2017-3-31
When you put all of the data into one matrix then your task is easy:
>> M = [95, 1, 10.9831, 8.9874;...
2, 45, 1.6000, 7.1402;...
3, 76, 1.7000, 9.3224;...
4, 88, 1.6100, 9.5381;...
5, 55, 1.5000, 7.4204;...
6, 50, 1.6100, 7.5010;...
7, 61, 1.5800, 8.0519;...
8, 105, 1.8300, 11.2821];
>> fmt = '%3d,%4d,%6.2f,%6.2f\n';
>> fprintf(fmt,M.')
95, 1, 10.98, 8.99
2, 45, 1.60, 7.14
3, 76, 1.70, 9.32
4, 88, 1.61, 9.54
5, 55, 1.50, 7.42
6, 50, 1.61, 7.50
7, 61, 1.58, 8.05
8, 105, 1.83, 11.28
Note that I specified different formats for each column, and used transpose M.' instead of the linear algebra operation ctranspose M'.

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