Convert a string in cell into numbers.

2017 4 1
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I have: X = 1x1 struct X.T = 27919x1 cell and for example X.T(1,1) = 3,7,12,16 like char. I'd like to have X.T(1,1) like 1x4 double with 4 numeric value. How can I do this? Thank you in advance

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the cyclist
the cyclist 2017-4-1
A couple questions:
Do you mean that X.T(1,1) is a character array that includes the commas, as in
'3,7,12,16'
Or something else?
Is all of X.T like that, such that you want to convert the entire cell array from such character arrays to numeric? Or do you just want to do specific elements that you will index into?
Riccardo Cosmai
Riccardo Cosmai 2017-4-1
yes includes commas. And i want to for example 3 like a specific element, 7 like an other specific element,... then a row 4x1 with numeric elements

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the cyclist
the cyclist 2017-4-1

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% Defining an example cell array that contains a character array.
a{1,1} = '3,7,12,16';
% Convert the contents of that element to a numeric array
a{1,1} = str2num(a{1,1})

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Riccardo Cosmai
Riccardo Cosmai 2017-4-1
Thank you so much. I resolve with this:
for i=1:27919
X.T{i,1}=str2num(X.T{i,1});
end
the cyclist
the cyclist 2017-4-1
编辑：the cyclist 2017-4-1
You can do this more compactly like this:
X.T = cellfun(@str2num,X.T,'UniformOutput',false)
The reason I did not suggest this originally is that I thought you only wanted to convert individual elements, not the whole thing.

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