Replace 1's with 0's if there is less that five 1's between 0's in vector

Question

Eric 2017-4-1

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https://ww2.mathworks.cn/matlabcentral/answers/333145-replace-1-s-with-0-s-if-there-is-less-that-five-1-s-between-0-s-in-vector

回答： the cyclist 2017-4-1

Hi everyone,

I want to replace 1's with 0's if there are less than five 1's between the zeros in a large vector. For example, I have the following vector:

x = [1; 1; 1; 1; 1; 1; 0; 1; 1; 1; 0; 1; 1; 1; 1; 1; 1; 0; 1; 1; 1; 1; 1; 1; 1; 0];

And I would like to create a script that can find and replace only the 1's where there are less than five 0's in between, which would end up with the following results with the example from above:

x = [1; 1; 1; 1; 1; 1; 0; 0; 0; 0; 0; 1; 1; 1; 1; 1; 1; 0; 1; 1; 1; 1; 1; 1; 1; 0];

Thanks a lot in advance,

Eric

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Answer 1

the cyclist 2017-4-1

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https://ww2.mathworks.cn/matlabcentral/answers/333145-replace-1-s-with-0-s-if-there-is-less-that-five-1-s-between-0-s-in-vector#answer_261374

在 MATLAB Online 中打开

Here is one way:

Download Jan Simon's RunLength code from the File Exchange. Then,

x = [1; 1; 1; 1; 1; 1; 0; 1; 1; 1; 0; 1; 1; 1; 1; 1; 1; 0; 1; 1; 1; 1; 1; 1; 1; 0];
[b n bi] = RunLength(x);    
shortOneRunIndex = find(b'==1 & n<5);
for ns = shortOneRunIndex
    x(bi(ns):bi(ns+1)-1) = 0;
end

This algorithm assumes that the sequence ends with a zero, as your example did. It could be fixed up to not require that assumption.