How can i coda this process?
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x=((0*-0.15)+(-7.50*-1.25)+(-9.50*-1.40)+(-5.81*-1.32)+(2.15*-1.28)+(10.20*-0.15)+(7.50*0))
%
h=((0*-7.50)+(-0.15*-9.50)+(-1.25*-5.81)+(-1.40*2.15)+(-1.32*10.20)+(-1.28*7.50)+(-0.15*0))
%
2*F=x-h
How can i coda this process?
4 个评论
John D'Errico
2017-4-1
编辑:John D'Errico
2017-4-1
What process? Only you know what the notation you have there means. Anyway, it seems like you have written something, although
2*F = x-h
is not valid syntax.
Muhendisleksi
2017-4-1
John D'Errico
2017-4-1
Ok. So you wrote it. What is the problem?
Muhendisleksi
2017-4-1
回答(0 个)
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