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Dont get the required answer..please help

1 次查看（过去 30 天）
Aarach Sap
Aarach Sap 2017-4-4
关闭： MATLAB Answer Bot 2021-8-20
A=[2 5 3 1 1 ; 4 2 5 1 1];
[r,c]=size(A);
B=[1 0 1 1 1; 1 0 1 1 1 ];
[m,n]=size(B);
for row=1:r
for col=1:c
for ii=1:m
for jj=1:n
if (A(row,col)==5)&&(B(ii,jj)==1)
A(row,col)=5+1;
end
end
end
end
end
In the above code, if A has 5 and B has 1 then it should be 6 but if A has 5 but B has 0 then it should be 5. I know its simple. But i am not getting where i am wrong.

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回答（2 个）

Guillaume
Guillaume 2017-4-4
编辑：Guillaume 2017-4-4
Is
A=[2 5 3 1 1 ; 4 2 5 1 1];
B=[1 0 1 1 1; 1 0 1 1 1 ];
A(A == 5 & B) = 6
what you're looking for?
edit, or maybe:
B = logical(B);
A(B) = A(B) + 1
  2 个评论
John D'Errico
John D'Errico 2017-4-4
Note that the second solution shown will increment ALL values of A where B == 1. That may or may not be the desired goal. But in that case, it would be as simple to write A=A+B.
Guillaume
Guillaume 2017-4-4
Indeed! I was too focused on demonstrating logical indexing that I missed the simple addition.
Rik
Rik 2017-4-4
I am going to assume you want the following: A should stay the same, except for some positions. On the positions that A is 5 and B is 1, then A should be 6.
You can solve this without the hassle of 4 nested loops if you use logical indexing.
A(A==5 & B==1)=6;
(Technically, B==1 can be replaced with B, because it already contains only ones and zeros, but this is a more general case)
If this is not what you need, please elaborate on your question. If it is, please mark this answer as accepted answer.

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